x = (1/2)(2x -2 ) +1 ∫x/(x^2-2x-3) dx=(1/2)∫(2x-2)/(x^2-2x-3) dx + ∫dx/(x^2-2x-3)=(1/2)ln|x^2-2x-3| + (1/4)∫ [1/(x-3) -1/(x+1) ] dx=(1/2)ln|x^2-2x-3| + (1/4)ln|(x-3)/(x+1)| + C
