3^m=6，9^n=2，即3^2n=23^(2m-4n+1)=(3^2m)÷(3^4n)×3 =((3^m)^2)÷((3^2n)^2)×3 =36÷4×3 =27
解3^m=6,9^n=2即3^2n=2∴3的2m-4n+1次方=3的2m次方÷3的4n次方×3=(3^m)²÷(3^2n)²×3=6²÷2²×3=9×3=27
3^2m-4n 1=(3m)^2÷(3^2n)^2×3=9×3=27
