58问答库 > 往硫酸铝铵 NH4Al（SO4）2溶液中滴加Ba（OH）2溶液并加热，刚好使NH4+全部转化为NH3，写出反应的离方程式

往硫酸铝铵 NH4Al（SO4）2溶液中滴加Ba（OH）2溶液并加热，刚好使NH4+全部转化为NH3，写出反应的离方程式

2025-03-27 17:52:46
推荐回答（1个）
回答（1）：

NH4Al（SO4）2溶液与Ba（OH）2溶液应按照物质的量之比1：2反应刚好使NH4+全部转化为NH3反应的离子方程式为：NH4++Al3++2SO42-+2Ba2++4OH-

  △  
 
NH3↑+Al（OH）3↓+2BaSO4↓+H2O；
故答案为：NH4++Al3++2SO42-+2Ba2++4OH-
  △  
 
NH3↑+Al（OH）3↓+2BaSO4↓+H2O．

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