应该是(0,-3)y'=-2x+4x=0,k=y'=4x=3,k=y'=-2所以切线是y+3=4(x-0),y-0=-2(x-3)即y=4x-3和y=-2x+6交点是(3/2,3)所以面积=∫(0到3/2)[4x-3-(-x²+4x-3)]dx+∫(3/2到3)[-2x+6-(-x²+4x-3)]dx=(x³/3)(0到3/2)+(x³/3-3x²+9x)(3/2到3)=(9/8)+(9-63/8)=9/4
