初二数学几何应用题

解:设小正方形的边长为X.
(360-2x)(265-2x)=720
95400-530x-720x+4x^2=720
4x^2-1250x+94680=0
x^2-312.5x+23670=0
x^2-2*156.25*x+24414.0625=744.0625
(x-156.25)^2=744.0625
X=(约)27+\-156.25
X1=183.25 X2=-129.25(舍去)
答: 盒子的高是183.25cm.
(你确定题没错吗????)

解：设高为X
则（360-x)(265-x)=72000
进行因式分解得出(x-40)(x-585)=0
x1=40
x2=580
因x2不合题意，舍去。
所以高是40mm

解:设小正方形的边长为X.
(360-2x)(265-2x)=720
95400-530x-720x+4x^2=720
4x^2-1250x+94680=0
x^2-312.5x+23670=0
x^2-2*156.25*x+24414.0625=744.0625
(x-156.25)^2=744.0625
X=(约)27+\-156.25
X1=183.25 X2=？？？？？？？？？？？反正不=2