求高人解答 -4눀*[(1-7)÷6]대+[(-5)대-3]÷(-2)대

2024-11-16 02:20:50
推荐回答(3个)
回答(1):

(-1/42)÷[1/2-1/3+5/7+(-2/3)^*(-6)] =-1/42÷[1/6+5/7+4/9*(-6)] =-1/42÷[37/42-8/3] =-1/42÷(-25/14) =1/75. 解2 被除数、除数都乘以42,得 原式=-1÷[21-14+30-112] =-1÷(51-126) =1/75.

回答(2):

解: 原式 =1/42÷[1/2-1/3+5/7+4/9*(-6)] =1/42÷[3/6-2/6+5/7-8/3] =1/42÷[1/6+5/7-16/6] =1/42÷[7/42+30/42-112/42] =1/42÷(37-112)/42 =1/42×42/(-75) =-1/75

回答(3):

(5/6-3/4)÷5/12÷9/5 = (5/6-3/4)*12/5*5/9 = (5/6-3/4)*4/3=5/3-1=2/3