分别利用while 循环..for循环编程，打印出1~100之间能被9整除的所有整数？

FOR循环
for(int i=1;i<=100;i++)
{
if(i%9==0)
{
System.out.println(i); //Console.WriteLine(i);
}
}
While循环
int i=1;
WHILE(i<=100)
{
if(i%9==0)
{
System.out.println(i); //Console.WriteLine(i);
}
i++;
}

//下面是do-while和for循环
int a=0;
int i;
do{
for(i=1;i<=100;i++){
if(i%9==0){
System.out.println(i);//输出能被9整除的数

}
}
}while(i<100);
//下面是while和for循环
int a=0;
int i;
while(i<100){
for(;i<=100;i++){
if(i%9==0){
System.out.println(i);//输出能被9整除的数
}
}
}

C++程序

WHILE循环：

//---------------------------------------------------------------------------

#include

int main(void)
{
int i=1;
while (i*9<100)
std::cout< return 0;
}
//---------------------------------------------------------------------------

FOR循环：
//---------------------------------------------------------------------------

#include

int main(void)
{
int i;
for (i=1; i*9<100; i++) {
std::cout<}
return 0;
}
//---------------------------------------------------------------------------

DO-WHILE循环：

//---------------------------------------------------------------------------

#include

int main(void)
{
int i=1;
do
{
std::cout< }while (i*9<100);
return 0;
}
//---------------------------------------------------------------------------

FOR循环
for(int
i=1;i<=100;i++)
{
if(i%9==0)
{
System.out.println(i);
//Console.WriteLine(i);
}
}
While循环
int
i=1;
WHILE(i<=100)
{
if(i%9==0)
{
System.out.println(i);
//Console.WriteLine(i);
}
i++;
}