设首蠢转化率为x反应后，c(CO)=c(H2O)=0.01*(1-x)mol/L,c(CO2)=c(H2)=0.01xmol/闹链L平衡常数=c(CO2)*c(H2)/[c(CO)*c(H2O)]=(0.01x)^2/{[0.01*(1-x)]^2}=(x^2)/[(1-x)^2]=9.4解得，液芹孙x=75.4%
