函数y=(x-1)눀(x-2)대的单调区间为?

2024-11-15 15:33:41
推荐回答(2个)
回答(1):


回答(2):

y=(x-1)^2*(x-2)^3y'=2(x-1)(x-2)^3+3(x-1)^2(x-2)^2=(x-1)(x-2)^2[2(x-2)+3((x-1)]=(x-1)(x-2)^2(5x-7)y'>0==>x7/5y'1