求五子棋c或c++代码

2024-11-17 12:29:59
推荐回答(3个)
回答(1):

五子棋C原码
/*turboc2.0下编译通过*/

#i nclude

#i nclude

#i nclude

#i nclude

#define N 15

#define B 7

#define STOP -10000

#define OK 1

#define NO 0

#define UP 328

#define DOWN 336

#define LEFT 331

#define RIGHT 333

/*定义了两个数,n为棋盘的大小。b为背景颜色的数值*/

int a[N+1][N+1];

int zx,zy;

int write=1,biaoji=0;

struct zn{

long sum;

int y;

int x;

}w[N+1][N+1],max,max1;

void cbar(int i,int x,int y,int r);

void map(int a[][]);

int getkey();

int key();

void zuobiao(int x,int y,int i);

int tu(int a[][],int write);

int wtu(int a[][],int write);

int zhineng(int a[][]);

int zh5(int y,int x,int a[][]);

long zzh5(int b[][],int i);

main()

{

int i,j;

int gdriver=DETECT;

int gmode;

initgraph(&gdriver,&gmode,"");

zx=(N+1)/2;

zy=(N+1)/2;

for(i=1;i<=N;i++)

for(j=1;j<=N;j++)

a[i][j]=0;

map(a);

i=1;

while(i)

{

int k,n;

k=wtu(a,write);

if(k==STOP) goto end;

map(a);

n=zhineng(a);

if(n==STOP) goto end;

map(a);

}

end:

;

}

/* 实现对局的程序 ,计算全部N*N个格中,最应该填的格子 */

int zhineng(int a[N+1][N+1])

{

int i,j;

int k;

max.sum=-1;

for(i=0;i<=N;i++)

for(j=0;j<+N;j++)

{

w[i][j].sum=0;

w[i][j].x=i;

w[i][j].y=j;

}

for(i=1;i<=N-4;i++)

for(j=1;j<=N-4;j++)

{

k=zh5(i,j,a);

if(k==STOP) return (STOP);

}

for(i=1;i<=N;i++)

for(j=1;j<=N;j++)

{

if(max.sum
{

max.sum=w[i][j].sum;

max.y=i;

max.x=j;

}

else if(max.sum==w[i][j].sum)

{

if(((max.y-zy)*(max.y-zy)+(max.x-zx)*(max.x-zx))>((i-zy)*(i-zy)+(j-zx)*(j-zx)))

max.sum=w[i][j].sum;

max.y=i;

max.x=j;

}

}

if(a[max.y][max.x]==0)

{

a[max.y][max.x]=-1;

zy=max.y;

zx=max.x;

}

}

/* 转换成5*5的数组,计算出在二十五个格子中,最应该填的格 */

int zh5(int y,int x,int a[N+1][N+1])

{

int i,j;

int b[6][6];

long c[13];

long d[6][6];

long temp;

for(i=y;i<=y+4;i++)

for(j=x;j<=x+4;j++)

b[i+1-y][j+1-x]=a[i][j];

c[1]=b[1][1]+b[1][2]+b[1][3]+b[1][4]+b[1][5];

c[2]=b[2][1]+b[2][2]+b[2][3]+b[2][4]+b[2][5];

c[3]=b[3][1]+b[3][2]+b[3][3]+b[3][4]+b[3][5];

c[4]=b[4][1]+b[4][2]+b[4][3]+b[4][4]+b[4][5];

c[5]=b[5][1]+b[5][2]+b[5][3]+b[5][4]+b[5][5];

c[6]=b[1][1]+b[2][1]+b[3][1]+b[4][1]+b[5][1];

c[7]=b[1][2]+b[2][2]+b[3][2]+b[4][2]+b[5][2];

c[8]=b[1][3]+b[2][3]+b[3][3]+b[4][3]+b[5][3];

c[9]=b[1][4]+b[2][4]+b[3][4]+b[4][4]+b[5][4];

c[10]=b[1][5]+b[2][5]+b[3][5]+b[4][5]+b[5][5];

c[11]=b[1][1]+b[2][2]+b[3][3]+b[4][4]+b[5][5];

c[12]=b[1][5]+b[2][4]+b[3][3]+b[4][2]+b[5][1];

for(i=1;i<=12;i++)

{

switch(c[i])

{

case 5:biaoji=1;return(STOP);

case -5:biaoji=-1;return(STOP);

case -4:c[i]=100000;break;

case 4:c[i]=100000;break;

case -3:c[i]=150;break;

case 3:c[i]=150;break;

case -2:c[i]=120;break;

case 2:c[i]=100;break;

case -1:c[i]=1;break;

case 1:c[i]=1;break;

default: c[i]=0;

}

}

for(i=1;i<=12;i++)

{

if(c[i]==150)

c[i]+=zzh5(b,i);

}

for(i=1;i<=5;i++)

for(j=1;j<=5;j++)

d[i][j]=0;

for(i=1;i<=5;i++)

for(j=1;j<=5;j++)

{

if(i==j) d[i][j]+=c[11];

if((i+j)==6) d[i][j]+=c[12];

d[i][j]+=c[i]+c[j+5];

}

for(i=1;i<=5;i++)

for(j=1;j<=5;j++)

{

if(b[i][j]!=0)

d[i][j]=-2;

}

max1.sum=-1;

max1.y=0;

max1.x=0;

for(i=1;i<=5;i++)

for(j=1;j<=5;j++)

{

if(max1.sum
{

max1.sum=d[i][j];

max1.y=i;

max1.x=j;

w[i+y-1][j+x-1].sum+=max1.sum;

}

else if(max1.sum==d[i][j])

{

if(((i+y-1-zy)*(i+y-1-zy)+(j+x-1-zx)*(j+x-1-zx))>((max1.y+y-1-zy)*(max1.y+y-1-zy)+(max1.x+x-1-zx)*(max1.x+x-1-zx)))

{

max1.sum=d[i][j];

max1.y=i;

max1.x=j;

}

}

}

}

long zzh5(int b[6][6],int n)

{

int i,j,k,l,m;

switch(n)

{

case 1:i=b[1][1];j=b[1][2];k=b[1][3];l=b[1][4];m=b[1][5];break;

case 2:i=b[2][1];j=b[2][2];k=b[2][3];l=b[2][4];m=b[2][5];break;

case 3:i=b[3][1];j=b[3][2];k=b[3][3];l=b[3][4];m=b[3][5];break;

case 4:i=b[4][1];j=b[4][2];k=b[4][3];l=b[4][4];m=b[4][5];break;

case 5:i=b[5][1];j=b[5][2];k=b[5][3];l=b[5][4];m=b[5][5];break;

case 6:i=b[1][1];j=b[2][1];k=b[3][1];l=b[4][1];m=b[5][1];break;

case 7:i=b[1][2];j=b[2][2];k=b[3][2];l=b[4][2];m=b[5][2];break;

case 8:i=b[1][3];j=b[2][3];k=b[3][3];l=b[4][3];m=b[5][3];break;

case 9:i=b[1][4];j=b[2][4];k=b[3][4];l=b[4][4];m=b[5][4];break;

case 10:i=b[1][5];j=b[2][5];k=b[3][5];l=b[4][5];m=b[5][5];break;

case 11:i=b[1][1];j=b[2][2];k=b[3][3];l=b[4][4];m=b[5][5];break;

case 12:i=b[1][5];j=b[2][4];k=b[3][3];l=b[4][2];m=b[5][1];break;

}

if((i==0&&j==1&&k==1&&l==1&&m==0))

return (900);

if((i==0&&j==-1&&k==-1&&l==-1&&m==0))

return(1000);

if((i==0&&j==0&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==0&&m==0))

return(20);

if((i==0&&j==0&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==0&&m==0))

return(20);

if((i==-1&&j==1&&k==1&&l==1&&m==1)||(i==1&&j==-1&&k==1&&l==1&&m==1)||(i==1&&j==1&&k==-1&&l==1&&m==1)||(i==1&&j==1&&k==1&&l==-1&&m==1)||(i==1&&j==1&&k==1&&l==1&&m==-1))

return(-60);

if((i==1&&j==-1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==1&&k==-1&&l==-1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==1&&m==-1)||(i==-1&&j==-1&&k==-1&&l==-1&&m==1))

return(-60);

}

/* 循环执行坐标的选择,直到按回车,空格或ESC键 */

int wtu(int a[N+1][N+1],int write)

{

int i=1;

map(a);

zuobiao(zx,zy,1);

while(i)

{

int k;

k=tu(a,write);

if(k==OK) i=0;

if(k==STOP) return (STOP);

}

}

/*从键盘获得输入的值*/

int getkey()

{

int key,lo,hi;

key=bioskey(0);

lo=key&0x00ff;

hi=(key&0xff00)>>8;

return((lo==0) ? hi+256:lo);

}

/*对获得的值进行判断*/

/*对应的码值分别如下*/

/* 上:328 下:336 左: 331 右: 333 */

/* 回车:13 ESC键: 27 */

int key()

{

int k;

k=getkey();

switch(k)

{

case 27: return (STOP);

case 13:

case ' ': return (OK);

case 328: return (UP);

case 336: return (DOWN);

case 331: return (LEFT);

case 333: return (RIGHT);

default: return (NO);

}

}

/*用来显示坐标的位置*/

void zuobiao(int x,int y,int i)

{

int r;

if(i!=0)

{

setcolor(GREEN);

for(r=1;r<=5;r++)

circle(75+25*x,25+25*y,r);

}

else

{

if(a[zy][zx]==1)

{

setcolor(8);

for(r=1;r<=5;r++)

circle(75+25*x,25+25*y,r);

}

else if(a[zy][zx]==-1)

{

setcolor(WHITE);

for(r=1;r<=5;r++)

circle(75+25*x,25+25*y,r);

}

else

{

setcolor(B);

for(r=1;r<=5;r++)

circle(75+25*x,25+25*y,r);

setcolor(RED); line(75+25*zx-5,25+25*zy,75+25*x+5,25+25*zy);

line(75+25*zx,25+25*zy-5,75+25*zx,25+25*zy+5);

}

}

}

/*从键盘获得的值进行判断,反映在显示的图上*/

int tu(int a[N+1][N+1],int write)

{

int k;

re:

k=key();

if(k==OK)

{

if(a[zy][zx]==0)

{

a[zy][zx]=write;

}

else

goto re;

}

if(k==STOP) return(STOP);

if(k==NO) goto re;

if(k==UP)

{

int i,j;

if(zy==1) j=zy;

else j=zy-1;

zuobiao(zx,zy,0);

zuobiao(zx,j,1);

zy=j;

goto re;

}

if(k==DOWN)

{

int i,j;

if(zy==N) j=zy;

else j=zy+1;

zuobiao(zx,zy,0);

zuobiao(zx,j,1);

zy=j;

goto re;

}

if(k==LEFT)

{

int i,j;

if(zx==1) i=zx;

else i=zx-1;

zuobiao(zx,zy,0);

zuobiao(i,zy,1);

zx=i;

goto re;

}

if(k==RIGHT)

{

int i,j;

if(zx==N) i=zx;

else i=zx+1;

zuobiao(zx,zy,0);

zuobiao(i,zy,1);

zx=i;

goto re;

}

}

/* 根据数组中(存储棋子位置)各位置的数,画实心圆(画出棋子)*/

void cbar(int i,int x,int y,int r)

{

if(i!=0)

{

if(i==1)

setcolor(8);

else if(i==-1)

setcolor(WHITE);

for(i=1;i<=r;i++)

{

circle(x,y,i);

}

}

}

/*画出棋盘,和各个棋子*/

void map(int a[N+1][N+1])

{

int i,j;

cleardevice();

setbkcolor(B);

setcolor(RED);

for(i=0;i
{

line(100,50+25*i,75+N*25,50+25*i);

line(100+25*i,50,100+25*i,25+N*25);

}

for(i=1;i<=N;i++)

for(j=1;j<=N;j++)

cbar(a[i][j],75+25*j,25+25*i,10);

}

回答(2):

要得话留下邮箱,给我留言或直接Hi我,我发给你。

回答(3):

是网络的吗?可视化界面还是单纯的控制台界面?去VC区问问吧。

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