∫x⼀cosxcosxdx

2024-12-01 23:03:27
推荐回答(1个)
回答(1):

∫xcos²xdx=∫x(1+cos2x)/2dx=1/2(∫xdx+∫xcos2xdx)
=1/2(1/2x²+∫xcos2xdx)
=1/2(1/2x²+1/2∫xdsin2x)
=1/2(1/2x²+1/2(xsin2x-∫sin2xdx))
=1/2(1/2x²+1/2xsin2x+1/4cos2x)+C