if i mod 2=0 then
range("B"& i)=range("B"& i-1)*1.1
else
range("B"& i)=range("B"& i-1)*0.9
end if
sub test()
dim i as integer
dim n
for i = 2 to 65536 '从第二行开始
n = i mod 2
if n = 1 then
range("B"& i)=range("B"& i-1)*0.9
else
range("B"& i)=range("B"& i-1)*1.1
end if
next
end sub
mod(row(B1),2)=1(余数为1) 则为奇数行
mod(row(B1),2)=0 则为偶数行
= 1 = 2 .9
else
range("B"i)=range("B"to B"& B"& 65536 '从第二行开始
 sub test()
dim range("i mod 2
if n & i)=range(" i as integer
dim n
end if
next
end n = i-1)*1.1
& i-1)*0; for i then
 
B2=BI*(MOD(1.1-ROW(B1),2)*0.2)