用分解因式解下列方程: (2x+3)∧2=4(2x+3); 2(x-3)∧2=x∧2-9

2024-11-28 08:23:11
推荐回答(1个)
回答(1):

(1) (2x+3)∧2=4(2x+3)
  (2x+3)∧2-4(2x+3)=0
  (2x+3)(2x+3-4)=0
  (2x+3)(2x-1)=0
  2x+3=0 2x-1=0
 亩乱 x=-3/2 x=1/2
(2) 2(x-3)∧2=x∧2-9
  2(x-3)∧纤耐含毁笑2-(x+3)(x-3)=0
  (x-3)(2x-6-x-3)=0
  (x-3)(x-9)=0
  x-3=0 x-9=0
   x=3 x=9