(1)2sinAcosC-(2sinB-sinC)=0 2sinAcosC-(2sin(A+C)-C)=0 2sinAcosC-(2sinAcosC+cosAsinC-sinC)=0 2sinAcosC=2sinAcosC+cosAsinC-sinC 因为sinA>0,cosC>0所以cosAsinC-sinC=0 cosAsinC=sinC cosA=sinC÷sinC=1 所以A=0°亲,如果你做过此题,希望,你能和我交流一下,我也是刚刚做的。谢谢