在100到999之间有()个自然数,十位上的数字等于百位与个位上的数字之和
思路过程
推荐回答(3个)
答:
100到999之间,十位数等于百位数与个位数之和
十位数为1:110,1个自然数
十位数为2:121,220,2个自然数
十位数为3:132,231,330,3个自然数
十位数为4:143,242,341,440,4个自然数
....
十位数为9:198、297、396,495,594,693,792,891,990,9个自然数
所以共有:1+2+3+...+9=(1+9)*9/2=45个
在100到999之间有(45)个自然数,十位上的数字等于百位与个位上的数字之和
十位上的数字等于百位与个位上的数字之和
十位是 1 则 是110
十位是2 则 是 121 220
十位是3 则 是 132 231 330
十位是4 则 是 143 341 242 440
十位是5 则 是 154 253 352 451 550
十位是6 则 是 165 264 363 462 561 660
十位是7 则是176 275 374 473 572 671 770
十位是8 则是187 286 385 484 583 682 781 880
十位是9 则是 198 297 396 495 594 693 792 891 990
共计 1+2+3+4+5+6+7+8+9=45个
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