2x^2-5x+3=0用配方法

2024-11-06 11:02:24
推荐回答(2个)
回答(1):

2x^2-5x+3=0
2(x²-5x/2)+3=0
2(x-5/4)²+3-25/8=0
2(x-5/4)²=1/8
(x-5/4)²=1/16
x-5/4=±1/4
x=1或x=3/2

十字相乘法
2x^2-5x+3=0
(2x-3)(x-1)=0
x=1或x=3/2

回答(2):

x²-5/2x+3/2=0
(x-5/4)²-25/16+3/2=0
(x-5/4)²=1/16
x-5/4=±1/4
x=1,或3/2