C语言编程题，求助大神

#include

#include

unsigned int CalcDayOfMonth(unsigned int year, unsigned int month);

bool IsLeapYear(unsigned int year);

struct Time

{

unsigned int year;

unsigned int month;

unsigned int day;

void setTime(unsigned int y = 1900, unsigned int m = 1, unsigned int d= 1)

{

year = y; month = m;

if (d > CalcDayOfMonth(year, month))

day = CalcDayOfMonth(year, month);

else

day = d;

}

Time operator-(Time& t)

{

Time tmp;

if (t > * this)

{

tmp = t;

t = *this;

*this = tmp;

}

else

tmp = *this;

if (tmp.day >= t.day)

{

tmp.day -= t.day;

}

else

{

tmp.day = CalcDayOfMonth(tmp.year, tmp.month-1) + tmp.day-t.day;

tmp.month--;

}

if (tmp.month >= t.month)

tmp.month -= t.month;

else

{

tmp.month = tmp.month + 12 - t.month;

tmp.year--;

}

tmp.year -= t.year;

Time tmp1 = t;

int d=0;

while (!(*this==tmp1))

{

tmp1.day++;

d++;

if (CalcDayOfMonth(tmp1.year, tmp1.month) < tmp1.day)

{

tmp1.day = 1;

tmp1.month++;

}

if (tmp1.month > 12)

{

tmp1.month = 1;

tmp1.year++;

}

}

printf("累计相差：%d天\n", d);

return tmp;

}

bool operator==(Time& t)

{

bool b=this->day == t.day && this->month == t.month && this->year == t.year;

return b;

}

bool operator>(Time& t)

{

if (this->year > t.year)

return true;

else if (this->year == t.year)

{

if (this->month > t.month)

return true;

else if (this->month == t.month)

{

if (this->day > t.day)

return true;

else

return false;

}

else

return false;

}

else

return false;

}

};

void show(Time t)

{

printf_s("%d年-%u月-%u日\n", t.year, t.month, t.day);

}

bool IsLeapYear(unsigned int year)

{

if ((year % 400 == 0) || (year % 100 != 0) && (year % 4 == 0))

return true;

return false;

}

unsigned int CalcDayOfMonth(unsigned int year, unsigned int month)

{

switch (month)

{

case 1:

case 3:

case 5:

case 7:

case 8:

case 10:

case 12:

return 31;

case 4:

case 6:

case 9:

case 11:

return 30;

case 2:

return IsLeapYear(year) ? 29 : 28;

}

return 0;//返回0则表示月份输入不正确

}

int main()

{

Time t1, t2;

printf_s("请输入两个时间(格式：年 月 日)：\n");

scanf_s("%u %u %u", &t1.year, &t1.month, &t1.day);

scanf_s("%u %u %u", &t2.year, &t2.month, &t2.day);

show(t1 - t2);

}

看不清可以发源码

求采纳

100不够帮你写的，思路哪里不懂，追问吧？