c语言编程题

求1到100的素数和，求代码

2024-11-18 02:40:15

推荐回答（4个）

回答（1）：

#include
#include
int main()
{
    unsigned int beg = 0, end = 0, tmp = 0, i = 0, j = 0;
    unsigned long sum  = 0;
    printf("\nInput begin and end numbers:\n");
    scanf("%d%d", &beg, &end);
    if (beg > end)
    {
        tmp = beg;
        beg = end;
        end = tmp;
    }
    printf("\nCalculate sum of prime numbers between [%d, %d]:\n", beg, end);
    for (i = beg; i <= end; ++i)
    {
        if (2 > i)
        {
            continue;
        }
        tmp = 1 + (int)sqrt((double)i);
        for (j = 2; j <= tmp; ++j)
        {
            if (0 == i % j)
            {
                break;
            }
        }
        if (j >= tmp || 2 == i)
        {
            sum += i;
            printf("i = %d\t", i);
        }
    }
    printf("\nsum = %d\n", sum);
    return 0;
}

Input begin and end numbers:
1 100
Calculate prime number between [1, 100]:
i = 2   i = 3   i = 5   i = 7   i = 11  i = 13  i = 17  i = 19  i = 23  i = 29
i = 31  i = 37  i = 41  i = 43  i = 47  i = 53  i = 59  i = 61  i = 67  i = 71
i = 73  i = 79  i = 83  i = 89  i = 97
sum = 1060

回答（2）：

#include
int IsPrime(int num)
{
int i=2;
for(;i<=num/2;i++)
if(0==num%i)
return 0;
return 1;
}
void main()
{
int sum=0;
int num;
for(num=2;num<=100;num++)
if(IsPrime(num))
sum+=num;
printf("%d ",sum);
}

------------物联网校企恋盟技术部

回答（3）：

#include #include
int prime(int num);
int main (void){
int i, sum = 0;
for (i=2; i<=100; i++)
{
if (prime(i))
{
sum = sum + i;
}
}
printf ("%d\n", sum);
return 0;
}

int prime(int num) {
int k,time;
double stop;
time=0;
stop=sqrt(num);
for(k=2;k<=stop;k++)
{
if(num%k==0)
{
time++;
}
}

if(time==0 && num>1)
{
return 1;
}
else return 0;
}

回答（4）：

#include
void main(){
int i,j,k=0,sum=0;
for(i=2;i<=10;i++){
k=0;
for(j=1;j<=i;j++){
if(i%j==0)
k++;
}
if(k==2)
sum+=i;
}
printf("%d\n",sum);
}