3x/(x-1)-2[1+1/(x-1)]^2=x/(x+1)3x/(x-1)-2x^2/(x-1)^2-x/(x+1)=0[3x(x-1)(x+1)-2x^2*(x+1)-x*(x-1)^2]/[(x+1)(x-1)^2]=0[x(3x^2-3-2x^2-2x-x^2+2x-1)]/[(x+1)(x-1)^2]=0-4x/[(x+1)(x-1)^2]=0-4x=0x=0