一道初二的数学题!请亲们快点哈!我在线等!急急急急急急~

麻烦吧过程写清楚哦!谢谢咯
2024-12-04 09:41:11
推荐回答(1个)
回答(1):

1/(x+1)÷x-2*(x²+3x+2)/(x²-4)
=1/(x+1)*1/(x-2)*(x+1)(x+2)/[(x-2)(x+2)]
=1/(x-2)²

[(a-b)/a²b]²÷([(a-b)/a]³*[ab²/(a²-b²)]
=(a-b)²/a^4b²×a³/(a-b)³×ab²/(a-b)(a+b)
=1/[(a+b)(a-b)²]