cos(α+π⼀3)=4⼀5 α属于(0,π⼀2) 则cos(2α+5π⼀12)=

2025-03-24 01:12:26
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α∈(0,π/2),
∴u=α+π/3的值域是(π/3,5π/6),
cosu=4/5,
∴sinu=3/5,
∴sin2u=2sinucosu=24/25,cos2u=2(cosu)^2-1=7/25,
2α+5π/12=2u-π/4,
∴cos(2α+5π/12)=(√2/2)cos2u+(√2/2)sin2u
=31√2/50.