=(根号3+根号2+根号3-根号2)*(根号3+根号2-根号3+根号2)=4根号6
(√3+√2)²-(√3-√2)²=[(√3+√2)+(√3-√2)][(√3+√2)-(√3-√2)]=(2√3)(2√2)=4√6
(√3+√2)²-(√3-√2)²=(√3+√2+√3-√2)(√3+√2-√3+√2)=(2√3)(2√2)=4√6
(根号3+根号2)²-(根号3-根号2)²=4×根号3×根号2=4根号6