本人大四(面向嵌入式和单片机的),要做毕设,求建议,以下是题目,本人成绩中下。

2024-12-10 19:52:20
推荐回答(4个)
回答(1):

如果你们有导师指导的话,最好选择一个能包含硬件和软件技术最多的了,我看这些题目,大部分仅仅涉及到一小个技术而已啊。
如果你以后想从事小型电子设备的开发,或者仅仅是电子设备软件开发,那么学软件才是重点,说实在,软件是个无底洞,内容多,提升空间很大。
如果以后想做控制,如自动化生产线,数字化设备方面的,那么单片机、传感器、仪器仪表这些是重点。
学习还是靠自己以后长期的自学吧,大学学的东西很少,而一个课程设计学到的也非常有限。
如果能选几个课程设计的话,可以综合一下,平常也跟同学多了解下别人的设计。
3,6,15,25,43,58,65,75,85 这些都比较贴近实际的应用,你可以根据自己的兴趣和弱点加强下。

回答(2):

智能玩具小车的设计与实现 程序 可以实现小车在红外遥控器下行驶 左转 右转 前进 后退 停止 要原理图的话 你懂的

#include
#include
#define uchar unsigned char
#define uint unsigned int

sbit IR=P3^2; //红外接口标志
sbit NEA1=P2^2;
sbit NEB1=P2^3;
sbit IN1=P2^0;
sbit IN2=P2^1;
sbit IN3=P2^4;
sbit IN4=P2^5;
char code Tab[16]="0123456789ABCDEF";

unsigned char irtime;//红外用全局变量
bit irpro_ok,irok;
unsigned char IRcord[4];
unsigned char irdata[33];
unsigned char TempData[16];
uchar a;

void Ir_work(void);
void Ircordpro(void);
void qian_jin(void);
void hou_tui(void);
void zuo(void);
void you(void);
void ting(void);
void zuo45(void);
void you45(void);
void delay(uchar t);

void delay(uchar t) //延时1ms
{
uchar i,j,k;
for(i=t;i>0;i--)
for(j=142;j>0;j--)
for(k=4;k>0;k--);

}
void DelayUs2x(unsigned char t)
{
while(--t);
}
void DelayMs(unsigned char t)
{

while(t--)
{
//大致延时1mS
DelayUs2x(245);
DelayUs2x(245);
}
}

void qian_jin(void)
{
IN1=0;
IN2=1;
IN3=0;
IN4=1;
NEA1=1;
NEB1=1;
}
void hou_tui(void)
{
IN1=1;
IN2=0;
IN3=1;
IN4=0;
NEA1=1;
NEB1=1;
}
void zuo(void)
{
IN1=0;
IN2=1;
IN3=1;
IN4=0;
NEA1=1;
NEB1=1;
}
void you(void)
{
IN1=1;
IN2=0;
IN3=0;
IN4=1;
NEA1=1;
NEB1=1;
}
void ting(void)
{
IN1=0;
IN2=0;
IN3=0;
IN4=0;
NEA1=0;
NEB1=0;
}
void zuo45(void)
{

IN1=0;
IN2=1;
IN3=1;
IN4=0;
NEA1=1;
NEB1=1;
delay(150);
delay(100);
}

void you45(void)
{

IN1=1;
IN2=0;
IN3=0;
IN4=1;
NEA1=1;
NEB1=1;
delay(150);
delay(100);
}
void tim0_isr (void) interrupt 1 using 1
{
irtime++; //用于计数2个下降沿之间的时间
}

void EX0_ISR (void) interrupt 0 //外部中断0服务函数
{
static unsigned char i; //接收红外信号处理
static bit startflag; //是否开始处理标志位
if(startflag)
{
if(irtime<63&&irtime>=33)//引导码 TC9012的头码,9ms+4.5ms
i=0;
irdata[i]=irtime;//存储每个电平的持续时间,用于以后判断是0还是1
irtime=0;
i++;
if(i==33)
{
irok=1;
i=0;
}
}
else
{
irtime=0;
startflag=1;
}
}

void TIM0init(void)//定时器0初始化
{
TMOD=0x02;//定时器0工作方式2,TH0是重装值,TL0是初值
TH0=0x00; //重载值
TL0=0x00; //初始化值
ET0=1; //开中断
TR0=1;
}
void EX0init(void)
{
IT0 = 1; //指定外部中断0下降沿触发,INT0 (P3.2)
EX0 = 1; //使能外部中断
EA = 1; //开总中断
}

void Ir_work(void)
{
TempData[0] = Tab[IRcord[0]/16]; //处理客户码
TempData[1] = Tab[IRcord[0]%16];
TempData[2] = '-';
TempData[3] = Tab[IRcord[1]/16]; //处理客户码
TempData[4] = Tab[IRcord[1]%16];
TempData[5] = '-';
TempData[6] = Tab[IRcord[2]/16]; //处理数据码
TempData[7] = Tab[IRcord[2]%16];
TempData[8] = '-';
TempData[9] = Tab[IRcord[3]/16]; //处理数据反码
TempData[10] = Tab[IRcord[3]%16];

irpro_ok=0;//处理完成标志
}
void Ircordpro(void)//红外码值处理函数
{
unsigned char i, j, k;
unsigned char cord,value;
k=1;
for(i=0;i<4;i++) //处理4个字节
{
for(j=1;j<=8;j++) //处理1个字节8位
{
cord=irdata[k];
if(cord>7) //大于某值为1,
value|=0x80;
if(j<8)
{
value>>=1;
}
k++;
}
IRcord[i]=value;
value=0;
}
irpro_ok=1;//处理完毕标志位置1
}

void main(void)
{
EX0init(); //初始化外部中断
TIM0init(); //初始化定时器

DelayMs(20); //延时有助于稳定

while(1)//主循环
{
if(irok) //如果接收好了进行红外处理
{ Ircordpro(); irok=0; }
if(irpro_ok)
{ Ir_work(); }

if(TempData[9]=='E' && TempData[10]=='3' )
{ a=0; }
if(TempData[9]=='E' && TempData[10]=='7' )
{ a=1; }
if(TempData[9]=='A' && TempData[10]=='D')
{ a=2; }
if(TempData[9]=='F' && TempData[10]=='7')
{ a=3; }
if(TempData[9]=='A' && TempData[10]=='5')
{ a=4; }
if(TempData[9]=='F' && TempData[10]=='3')
{ a=5; }
if(TempData[9]=='A' && TempData[10]=='1' )
{ a=6; }

switch(a)
{
case 0: ting(); break;
case 1: qian_jin(); break;
case 2: hou_tui(); break;
case 3: zuo(); break;
case 4: you(); break;
case 5: zuo45();a=0;TempData[10]='0'; break;
case 6: you45();a=0;TempData[10]='0'; break;
default: a=0; break;
}

}
}

回答(3):

这些个题目都不错,任何一个弄清楚了都有很大收获。建议你根据自己的工作目标来选,尽量选与要从事的工作有关的题目。如果实在没有可选,建议选个安卓的吧。19,20这两个。

回答(4):

你是要选题目还是?

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