∵四边形ABCD是菱形,∴AO=CO= 1 2 AC= 1 2 ×8=4,DO=BO,EO⊥AC,∵△EAC是等边三角形,∴EA=AC=8,在Rt△ABO中,BO= AB2?AO2 = 52?42 =3,∴DO=BO=3,在Rt△EAO中,EO= EA2?AO2 = 82?42 =4 3 .∴ED=EO-DO=4 3 -3.故答案为:4 3 -3.