(x+3除x-2)+(x+7除x+6)=(x+4除x+3) +(x+6除x+5)解方程

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2024-11-28 03:36:13
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回答(1):

(x+3)/(x+2)+(x+7)/(x+6)=(x+4)/(x+3)+(x+6)/(x+5)
1+1/(x+2)+1+1/(x+6)=1+1//(x+3)+1+1/(x+5)
1/(x+2)+1/(x+6)=1/(x+3)+1/(x+5)
(x+6+x+2)/(x+2)(x+6)=(x+5+x+3)/(x+3)(x+5)
(2x+8)/(x+2)(x+6)=(2x+8)/(x+3)(x+5)
∴2x+8=0,或者(x+2)(x+6)=(x+3)(x+5)
解得:x=-4
经检验是原方程的根