现有A~F六种常见的物质,其中B是食品包装中常用的干燥剂,A、B、C三种白色固体都含有同种金属元素,E是

2025-03-15 13:52:45
推荐回答(1个)
回答(1):


   (一)B物质是食品包装袋中常用的干燥剂,说明B为CaO,这是题目的突破口.
   (二)B可以转化为A,在初中范围内我们就知道CaO和水之间反应生成Ca(OH)2,而Ca(OH)2对应生成CaCO3(C),而C有可以转为CaO,这样就符合转化要求了.Ca(OH)2→CaCO3的路径不是唯一的,既可以与CO2反应,也可以与可溶性碳酸盐反应.
   (三)右侧的判断要从左侧的C的判断开始,C可以转为B,同时也可以转化为D,说明可能碳酸钙对应的是含碳的盐或者对应CO2.而D又可以转化为C,说明D为CO2
   (四)D、E、F含有相同的非金属元素,现在D含有碳元素和氧元素,而E是固体单质,说明是单指碳,即D、E、F共有的元素为碳元素.这样可以得出F为CO.同样在CO→CO2的路径也不是唯一的,既可以体现CO的可燃性,也可以体现还原性.不过选择自己最熟悉的反应书写.
故答案:
(1)CaCO3;CaO; C.
(2)A→C:Ca(OH)2+CO2═CaCO3↓+H2O或者Ca(OH)2+Na2CO3═CaCO3↓+2NaOH其他可溶性碳酸盐也可以
F→D:2CO+O2
 点燃 
 
2CO2或者CO+CuO
 高温 
 
CO2+Cu(其他金属氧化物也可以)

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