(x-1⼀2)(2x+1)(2x눀+1⼀2)除以(16x的四次方-1)等于几

2024-12-01 02:53:21
推荐回答(2个)
回答(1):

原式=1/4*(2x-1)(2x+1)/(4x²+1)/(16x^4-1)
=1/4*(4x²-1)/(4x²+1)/(16x^4-1)

=1/4*(16x^4-1)/(16x^4-1)
=1/4

回答(2):

原式=1/4*(2x-1)(2x+1)(4x²+1)/(4x²+1)/(16x^4-1)
=1/4*(4x²-1)/(4x²+1)/(16x^4-1)
=1/4*(16x^4-1)/(16x^4-1)
=1/4