58问答库 > 解方程:(x+2)⼀(x+1)-(x+4)⼀(x+3)=(x+6)⼀(x+5)-(x+8)⼀(x+7)

解方程:(x+2)⼀(x+1)-(x+4)⼀(x+3)=(x+6)⼀(x+5)-(x+8)⼀(x+7)

2024-11-18 03:20:46

推荐回答（2个）

回答（1）：

(x+2)/(x+1)-(x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7)
1-1/(x+1)-1-1/(x+3)=1+1/(x+5)-1-1/(x+7)
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)
2/((x+1)(x+3))=2/((x+5)(x+7))
(x+1)(x+3)=(x+5)(x+7)
x^2+4x+3=x^2+12x+35
8x=-32
x=-4

回答（2）：

解： x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7
(x+1+1)/(x+1)-(x+3+1)/(x+3)=(x+5+1)/(x+5)-(x+7+1)/(x+7)
(x+1)/(x+1)+1/(x+1)-(x+3)/(x+3)-1/(x+3)=(x+5)/(x+5)+1/(x+5)-(x+7)/(x+7)-1/(x+7)
1+1/(x+1)-1-1/(x+3)=1+1/(x+5)-1-1/(x+7)
1/(x+1)-1/(x+3)=1/(x+5)-1/(x+7)
(x+3)/(x+1)(x+3)-(x+1)/(x+1)(x+3)=(x+7)/(x+5)(x+7)-(x+5)/(x+5)(x+7)
2/(x+1)(x+3)=2/(x+5)(x+7)
(x+1)(x+3)=(x+5)(x+7)
x^2+4x+3=x^2+12x+35
8x=-32
x=-4。