甲乙两车分别从ab两地出发,相向而行,出发时,甲乙的速度比是4:5,相遇后,甲的速度增加20%,乙的速度减少

2024-11-05 22:53:39
推荐回答(2个)
回答(1):

相遇时,时间一定,路程与速度成正比例
甲行路程:乙行路程=甲速度:乙速度=4:5
甲行了全程的4/(4+5)=4/9,乙行了全程的5/(4+5)=5/9

相遇后,相同时间内,甲行路程:乙行路程=甲速度:乙速度=4×(1+20℅):5×(1-20℅)=6:5
甲行路程是乙的6/5,当乙到达a地时,乙又行了全程的4/9,甲应该行了全程的4/9×6/5=8/15

全程=15÷(5/9-8/15)=675千米

答:ab两地相距675千米。

回答(2):

相遇时,时间一定,路程与速度成正比例
甲行路程:乙行路程=甲速度:乙速度=4:5
甲行了全程的4/(4+5)=4/9,乙行了全程的5/(4+5)=5/9

相遇后,相同时间内,甲行路程:乙行路程=甲速度:乙速度=4×(1+20℅):5×(1-20℅)=6:5
甲行路程是乙的6/5,当乙到达a地时,乙又行了全程的4/9,甲应该行了全程的4/9×6/5=8/15

全程=15÷(5/9-8/15)=675千米

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