若|a-b-1|+(b-2a+c)的2次方+|2c-b|=0求abc的值 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0 x= y= z= |a-2b-4|+

2024-12-01 08:45:41
推荐回答(2个)
回答(1):

若|a-b-1|+(b-2a+c)的2次方+|2c-b|=0
则,必有:
a-b-1=0 (1)
b-2a+c=0 (2)
2c-b=0 (3)
(1)×2+(2)得:
-b+c=2 (4)
(3)-(4)得:
c=-2
代入(4)得:
b=-4
代入(1)得:a=-3
所以:a=-3;b=-4;c=-2

|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0
则,必有:
x+y+z=6 (1)
2x+3y-z=12 (2)
2x-y-z=0 (3)
(1)+(3)得:
3x=6
x=2
(1)+(2)得:
3x+4y=18
y=3
代入(3)得:
4-3-z=0
z=1
所以,x=2;y=3;z=1

回答(2):

若|a-b-1|+(b-2a+c)的2次方+|2c-b|=0

a-b=1
b-2a+c=0
b=2c

c=-2
b=-4
a=-3

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0
x+y+z=6
2x+3y-z=12
2x-y-z=0

x=2

y+z=4
3y-z=8
y=3
z=1