设x = siny，dx = cosy dy
当x = 0，y = 0；当x = 1/2，y = π/6
∫(0→1/2) √(1 - x²) dx
= ∫(0→π/6) √(1 - sin²y) • cosy dy
= ∫(0→π/6) cos²y dy
= (1/2)∫(0→π/6) (1 + cos2y) dy
= (1/2)(y + 1/2 • sin2y) |(0→π/6)
= (1/2)(π/6 + √3/4)
= (3√3 + 2π)/24
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