编写一汇编语言程序,要求从键盘接收一个四位的十六进制数,并在终端上显示与它等值的二进制数和十进制数
推荐回答(2个)
参考:
http://hi.baidu.com/%D7%F6%B6%F8%C2%DB%B5%C0/blog/item/a5fcfaf6a09cd93e730eeca8.html
;从键盘输入四位16进制数,以2进制、10进制输出
;=============================================
DATA SEGMENT
STR1 DB 'INPUT A HEX NUM: $'
HEX DB 5 ;计划输入的字符个数(含回车符)
NNN DB 0 ;存放实际输入的字符个数
DB 5 DUP(?)
BIN DW ? ;输入数字的二进制形式的存放单元
ERR DB 0AH, 0DH, ' ERROR !'
DB 0AH, 0DH, ' I HAVE NO TIME TO PLAY WITH YOU ! $'
STR2 DB 13, 10, 'BINARY IS: $'
DATA ENDS
;--------------------------------------------
STACK SEGMENT PARA STACK 'STACK'
DB 100 DUP(?)
STACK ENDS
;--------------------------------------------
CODE SEGMENT
ASSUME CS:CODE, SS:STACK, DS:DATA
START:
MOV AX, DATA
MOV DS, AX
MOV AX, STACK
MOV SS, AX
LEA DX, STR1 ;'INPUT A HEX NUM'
MOV AH, 9 ;显示字符串
INT 21H
LEA DX, HEX
MOV AH, 10 ;等着输入四位HEX数
INT 21H
;---------------------------------------
;下面进行转换
MOV BIN, 0 ;先把二进制数字单元清零
LEA SI, HEX + 2;取输入字符串的首地址
MOV CH, NNN ;取输入字符的个数,用来控制循环处理的次数
CONV:
MOV BL, [SI] ;取来一个字符
CMP BL, 0DH ;和回车符进行比较
JZ END0 ;是, 即结束
CMP BL, '0'
JB ERROR ;小于'0'转移
CMP BL, 'F'
JA ERROR ;大于'F'转移
CMP BL, '9'
JNA A2B ;不大于'9', 就去变换
CMP BL, 'A'
JNB A2B ;不小于'A', 就去变换
JMP ERROR ;其它符号都是错误
;---------------------------------------
A2B:
SUB BL, 30H ;ASC-->BIN
CMP BL, 10
JB A2B_END
SUB BL, 07H ;ASC-->BIN
A2B_END:
;---------------------------------------
MOV BH, 0 ;弄成16位数
PUSH CX
MOV AX, BIN ;把原来的数字乘以16
MOV CX, 16
MUL CX
ADD AX, BX ;加上新输入的
MOV BIN, AX ;存结果,这就是二进制数
INC SI
POP CX
DEC CH ;处理次数减一
JNZ CONV ;非零转移
;---------------------------------------
DISP:
LEA DX, STR2 ;'BINARY IS: $'
MOV AH, 9 ;显示字符串
INT 21H
;---------------------------------------
MOV AX, BIN ;取来数字
MOV CX, 16 ;显示16位数
DDDD:
MOV DL, '0' ;先计划显示0
TEST AX, 8000H ;测试最高位
JZ DDD1
INC DL ;非0就显示1
DDD1:
PUSH AX
MOV AH, 2 ;显示DL中的ASCII码
INT 21H
POP AX
SHL AX, 1 ;左移
LOOP DDDD ;CX-1,非零转移
JMP END0 ;16位显示完毕,转到结束
;---------------------------------------
ERROR:
LEA DX, ERR
MOV AH, 09H ;错误信息提示
INT 21H
;---------------------------------------
END0:
MOV DL, 10
MOV AH, 2 ;显示DL中的ASCII码
INT 21H
MOV DL, 13
MOV AH, 2 ;显示DL中的ASCII码
INT 21H
;---------------------------------------
MOV AX, BIN ;取来数字
CALL DISP_AX
MOV AH, 4CH ;返回DOS
INT 21H
;------------------------------
DISP_AX:
MOV BX, 10 ;10进制.
MOV CX, 5 ;5位.
ABC:
MOV DX, 0
DIV BX
PUSH DX ;保存余数
LOOP ABC
MOV CX, 5 ;显示5位.
ASD:
POP DX
CMP DL, 10
JB A48
ADD DL, 7
A48:
ADD DL, 48
MOV AH, 2
INT 21H ;输出.
LOOP ASD
RET
;------------------------------
CODE ENDS
;---------------------------------------
END START
;=============================================
程序执行效果如下:
c:\masm510>H_BD
INPUT A HEX NUM: D4A2
BINARY IS: 1101010010100010
54434
c:\masm510>
CODE SEGMENT
ASSUME CS:CODE
NUMBER DB 5,?,5 DUP(?)
LFCR DB 13,10,'$'
START: PUSH CS
POP DS
PUSH CS
POP ES
LEA DX,NUMBER
MOV AH,10
INT 21H
LEA DX,LFCR
MOV AH,9
INT 21H
LEA SI,NUMBER
ADD SI,2
MOV BP,0
MOV CX,4
CLD
@1:
PUSH CX
MOV CX,4
ROL BP,CL
LODSB
CALL ASCII2HEX
XOR AH,AH
ADD BP,AX
POP CX
LOOP @1
MOV AX,BP
MOV BX,10
CALL DSPAXX
MOV AX,BP
MOV BX,2
CALL DSPAXX
MOV AH,4CH
INT 21H
;===============================
ASCII2HEX PROC NEAR
CMP AL,'0'
JB @BYTE9
CMP AL,'9'
JA @BYTE2
AND AL,0FH
RET
@BYTE2:
CMP AL,'A'
JB @BYTE9
CMP AL,'F'
JA @BYTE4
SUB AL,37H
RET
@BYTE4:
CMP AL,'a'
JB @BYTE9
CMP AL,'f'
JA @BYTE9
SUB AL,57H
RET
@BYTE9:
MOV AL,0 ; 错误的输入当0对待
RET
ASCII2HEX ENDP
;================================
; 输出ax的值,输出的进位制在bx中设定,bx=2~16
DSPAXX PROC NEAR
PUSH AX
PUSH BX
PUSH CX
PUSH DX
PUSHF
XOR CX,CX
; MOV BX,16
@DSPAXX_1:
XOR DX,DX
DIV BX
INC CX
OR DX,30H
PUSH DX
CMP AX,0
JNE @DSPAXX_1
MOV AH,2
@DISPAXX_2:
POP DX
CMP DL,3AH
JB @DISPAXX_3
ADD DL,7
@DISPAXX_3:
INT 21H
LOOP @DISPAXX_2
MOV DL,32
INT 21H
POPF
POP DX
POP CX
POP BX
POP AX
RET
DSPAXX ENDP
;===============================
CODE ENDS
END START
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