那个二极管的或门电路是怎么回事?就是二极管的并联相当于什么?为什么它可以实现或门?

2025-04-03 11:26:54
推荐回答(4个)
回答(1):

你说的2个二极管并联应该是以二极管2个阳极为输入端,以二极管共阴极再通过一个电阻接地,并以阴极为输出端吧。
这运用的是二极管的单向导通性组成“或门”。你可以假设所有情况,得出真值表,
不难发现,当只要有一个输入为高电平“1”输出都会是高电平“1”,只有2个输入都为低电平“0”时,输出端才输出低电平“0”正好是或门的真值表。

回答(2):

或门就是在众多输入端(两个及以上)中,任何一个或者多个是高电位,那么在输出上(输出就一个端)就是高电位,两个二极管并联(负极并联),那么在两个正极上不论哪个是高电位(要大于二极管的门槛电压)那么在负极上就会有输出(也就是负极为高电位),与或门相反的是与门!!

回答(3):

二极管在逻辑电路中起开关作用,对于或门电路,当一个输入端为高电平时,相应的二极管导通,相当于开关接通,其他的输入为低电平的二极管由于是反向偏置,处于截止状态,相当于开关分断,电路的输出为高电平。从而实现输入输出的逻辑关系。

回答(4):

因为ecc为12v,二极管导通压降为0.7v。
a输入为0.7v,d1正向导通,并产生0.7v压降,f端为0.7+0.7=1.4v。
b输入为3v,但由於f点被d1拉低,d2反偏截止,对输出无影响。
a、b输入为3v时,就算理想中假设d1、d2同时导通,f点的电压为a加d1压降并联b加d2压降,所以输出为3.7v。

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