(x+2)(x-3)+2(x-1)(x-3)-3(x-1)(x+2)=0
化简后-12x+3=0
所以x=1/4
1/(x-1)+2/(x+2)-3/(x-3)=0
通分：
{(x+2)(x-3)+2(x-1)(x-3)-3(x+2)(x-1)}/{(x+2)(x-1)(x-3)}
= (x^2-x-6+2x^2-8x+6-3x^2-3x+6}/{(x+2)(x-1)(x-3)}
= (-12x+6}/{(x+2)(x-1)(x-3)}
= -12(x-1/2) / {(x+2)(x-1)(x-3)} = 0
x=1/2
两边同乘(x-1)(x+2)(x-3)得
(x+2)(x-3)+2(x-1)(x-3)-3(x-1)(x+2)=0
x^2-x-6+2(x^2-4x+3)-3(x^2+x-2)=0
-12x+6=0
x=1/2
1/2
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