先化简,再求值:(a+b)(a-b)+(4ab^3-8a^2b^2)÷4ab,其中a=2.b=1

2024-12-01 03:20:46
推荐回答(3个)
回答(1):

(a+b)(a-b)+(4ab^3-8a^2b^2)÷4ab
=a^2-b^2+b^2-2ab
=a^2-2ab
=a(a-2b)
=2x(2-2x1)
=0

回答(2):

=(a+b)(a-b)+4ab(b²-2ab)/4ab
=a²-b²+b²-2ab
=a(a-2b)
=2*(2-1*2)
=0

回答(3):

原式=a²-b²+4ab(b²-2ab)÷4ab=a²-b²+b²-2ab=a²-2ab=0