单片机开发板8*8点阵LED数码管如何显示一句话

回答（1）：

#include
typedef unsigned char uint8;
typedef unsigned int uint16;
typedef unsigned long uint32;

code uint8 graph[] = {0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xFF,0xC3,0xE7,0xE7,0xE7,0xE7,0xC3,0xFF,
0xFF,0x99,0x00,0x00,0x00,0x81,0xC3,0xE7,
0xFF,0x99,0x99,0x99,0x99,0x81,0xC3,0xFF,
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
};
sbit ENLED = P1^4;
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;

uint8 i= 0,counter = 0;

void timer1_init()
{
TMOD |= 0x10;
TMOD &= 0xdf;
TH1 = 0xFC;
TL1 = 0x67;
TR1 = 1;
}
void int_init()
{
ET1 = 1;
EA = 1;
}
void refresh_led()
{
static uint8 j = 0;
switch(j)
{
case 0: ADDR0 = 0;ADDR1 = 0;ADDR2 = 0;break;
case 1: ADDR0 = 1;ADDR1 = 0;ADDR2 = 0;break;
case 2: ADDR0 = 0;ADDR1 = 1;ADDR2 = 0;break;
case 3: ADDR0 = 1;ADDR1 = 1;ADDR2 = 0;break;
case 4: ADDR0 = 0;ADDR1 = 0;ADDR2 = 1;break;
case 5: ADDR0 = 1;ADDR1 = 0;ADDR2 = 1;break;
case 6: ADDR0 = 0;ADDR1 = 1;ADDR2 = 1;break;
case 7: ADDR0 = 1;ADDR1 = 1;ADDR2 = 1;break;
default: break;
}
P0 = graph[i + j];
if(7 == j++) j = 0;

}

main()
{
ENLED = 0; ADDR3 = 0;
timer1_init();
int_init();
while(1);

}
void interrupt_timer1() interrupt 3
{
TH1 = 0xFC;
TL1 = 0x67;
counter++;
if(counter == 200)
{
counter = 0;
i++;
if(i>=32){i=0;}
}
refresh_led();

}这程序显示字母I FC U 8*8太小了改下就可以了

回答（2）：

#include
typedef unsigned char uint8;
typedef unsigned int uint16;
typedef unsigned long uint32;

code uint8 graph[] = {0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xFF,0xC3,0xE7,0xE7,0xE7,0xE7,0xC3,0xFF,
0xFF,0x99,0x00,0x00,0x00,0x81,0xC3,0xE7,
0xFF,0x99,0x99,0x99,0x99,0x81,0xC3,0xFF,
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
};
sbit ENLED = P1^4;
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;

uint8 i= 0,counter = 0;

void timer1_init()
{
TMOD |= 0x10;
TMOD &= 0xdf;
TH1 = 0xFC;
TL1 = 0x67;
TR1 = 1;
}
void int_init()
{
ET1 = 1;
EA = 1;
}
void refresh_led()
{
static uint8 j = 0;
switch(j)
{
case 0: ADDR0 = 0;ADDR1 = 0;ADDR2 = 0;break;
case 1: ADDR0 = 1;ADDR1 = 0;ADDR2 = 0;break;
case 2: ADDR0 = 0;ADDR1 = 1;ADDR2 = 0;break;
case 3: ADDR0 = 1;ADDR1 = 1;ADDR2 = 0;break;
case 4: ADDR0 = 0;ADDR1 = 0;ADDR2 = 1;break;
case 5: ADDR0 = 1;ADDR1 = 0;ADDR2 = 1;break;
case 6: ADDR0 = 0;ADDR1 = 1;ADDR2 = 1;break;
case 7: ADDR0 = 1;ADDR1 = 1;ADDR2 = 1;break;
default: break;
}
P0 = graph[i + j];
if(7 == j++) j = 0;

}

main()
{
ENLED = 0; ADDR3 = 0;
timer1_init();
int_init();
while(1);

}
void interrupt_timer1() interrupt 3
{
TH1 = 0xFC;
TL1 = 0x67;
counter++;
if(counter == 200)
{
counter = 0;
i++;
if(i>=32){i=0;}
}
refresh_led();

}这程序显示字母I FC U 8*8太小了改下就可以了

回答（3）：

8*8只能显示字母或数字不能显示汉字除非是16*16的如果是单块点阵的花只能动态显示刷屏似的显示内容要想完整显示一句话需要拼接点阵否则不可以

回答（4）：

整块屏幕共有多少点阵？如果只能显示一个字，那你就循环显示啊，我建议用那些液晶显示屏吧，就十几块，而且字库都在里面了，只要给命令调用就好。

回答（5）：

就让它一个接一个显示呗