依次填：
slrk[i]或slrk[i]!='\0'或slrk[i]!=0
slrk[i]>='0' && slrk[i]<='9'——注意()中前面有个(，所以应该在'9'后加一个)以配对，若(是笔误则可不计
count(a)
strk[i]!='\0'
strk[i]>='0'&&strk[i]<='9'
count(a)
strk[i]!='\0'
strk[i]>='0')&&(strk[i]<='9')
count(a)
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