A、B、C、D四支球队进行足球比赛,每两队都要比赛一场,胜一场得3分,平一场得1分,负

A队二胜一负
B队二胜一平
C队一胜二负

我们来看看。ABC三支队胜场加起来有5场，而负场只有3场，那么
剩余的2个负场就在D队了；我们再看看B队平了一场，而A队和C队
都没有平的场次出现，显然B队是和D队打了一场平局。

那么D队的成绩就是一平两负积1分，ABCD四支球队的积分如下
A队二胜一负 6
B队二胜一平 7
C队一胜二负 3
D队一平二负 1
那么B队积7分就获得了本次比赛的冠军拉。

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A队二胜一负
B队二胜一平
C队一胜二负

我们来看看，AC两队都无平局。所以B和D打平，即D一平。ABC总共5胜3负，根据胜相等的关系，D2负，积分1分。

D队一平二负积一分