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58问答库 > 铅蓄电池中发生的总反应为：Pb+PbO2+2H2SO4=2PbSO4+2H2O,电极反应为：负极：？正极：？

铅蓄电池中发生的总反应为：Pb+PbO2+2H2SO4=2PbSO4+2H2O,电极反应为：负极：？正极：？

2025-04-01 18:07:06

推荐回答（2个）

回答（1）：

铅蓄电池反应为：Pb+PbO2+2H2SO4 ＝2PbSO4+2H2O。试写出放电和充电时的电极反应式。
解析：因为放电为原电池反应：Pb+PbO2+2H2SO4=2PbSO4+2H2O。Pb失电子发生负极反应，产生的Pb2+在H2SO4溶液中结合SO42-生成难溶于水的PbSO4，故其负极反应式为： Pb+SO42-－2e-=PbSO4

回答（2）：

（1)写出电极反应式
负极：pb+so4(2-)--2e==pbso4
正极：pbo2+4h(+)+so4(2-)+2e==pbso4+2h2o
（2）电解h2so4浓度怎么变化？
电解时，产生硫酸，所以硫酸浓度增大
（3）当通过1mol电子，负极增重多少克
负极：pb+so4(2-)--2e==pbso4
96
2
303
y=48克
1
x==151.5克
负极原本是pb,后生成pbso4,即增重的是so4(2-)的质量，所以增重48克

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