java 如何判断操作系统是Linux还是Windows

2024-11-04 17:57:45
推荐回答(2个)
回答(1):

System.out.println("===========os.name:"+System.getProperties().getProperty("os.name"));  
System.out.println("===========file.separator:"+System.getProperties().getProperty("file.separator"));

System类

public static Properties getProperties()

将 getProperty(String) 方法使用的当前系统属性集合作为 Properties 对象返回

 

 

键 相关值的描述

java.version    Java 运行时环境版本    

java.vendor    Java 运行时环境供应商    

java.vendor.url    Java 供应商的 URL    

java.home    Java 安装目录    

java.vm.specification.version    Java 虚拟机规范版本    

java.vm.specification.vendor    Java 虚拟机规范供应商    

java.vm.specification.name    Java 虚拟机规范名称    

java.vm.version    Java 虚拟机实现版本    

java.vm.vendor    Java 虚拟机实现供应商    

java.vm.name    Java 虚拟机实现名称    

java.specification.version    Java 运行时环境规范版本    

java.specification.vendor    Java 运行时环境规范供应商    

java.specification.name    Java 运行时环境规范名称    

java.class.version    Java 类格式版本号    

java.class.path    Java 类路径    

java.library.path    加载库时搜索的路径列表    

java.io.tmpdir    默认的临时文件路径    

java.compiler    要使用的 JIT 编译器的名称    

java.ext.dirs    一个或多个扩展目录的路径    

os.name    操作系统的名称    

os.arch    操作系统的架构    

os.version    操作系统的版本    

file.separator    文件分隔符(在 UNIX 系统中是“/”)    

path.separator    路径分隔符(在 UNIX 系统中是“:”)    

line.separator    行分隔符(在 UNIX 系统中是“/n”)    

user.name    用户的账户名称    

user.home    用户的主目录    

user.dir    用户的当前工作目录    

回答(2):



public class Judge
{
public static void main ( String[] args )

System.out.println (System.getProperty ("os.name"));
}
}

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