由题意可得, C = C ,解得n=9∵(x+ 1 2 x )9的展开式的通项为Tr+1= ( 1 2 )rC x9?rx? r 2 =( 1 2 )r C x9? 3r 2 令9- 3r 2 =6,解得r=2此时的系数为( 1 2 )2 C =9故答案为:9