因式分解法解下列方程 1.X²-7X+6=0 2.(5X-1)²=3(5X-1) 3.(2X-5)²-(X+4)²=0

2024-12-05 07:07:43
推荐回答(4个)
回答(1):

1.X²-7X+6=0
(X-6)(X-1)=0
X1=6 X2=1

2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
X1=1/5 X2=4/5

3.(2X-5)²-(X+4)²=0
4X²-20X+25-X²-8X-16=0
3X²-28X+9=0
(3X-1)(X-9)=0
X1=1/3 X2=9

回答(2):

1.X²-7X+6=0
(x-1)(x-6)=0
x-1=0,x-6=0
x=1, x=6

2.(5X-1)²=3(5X-1)
(5X-1)²-3(5X-1)=0
(5X-1)(5X-1-3)=0
5X-1=0,5X-4=0
x=0.2,x=0.8

3.(2X-5)²-(X+4)²=0
(2X-5+X+4)(2X-5-x-4)=0
3x-1=0,x-9=0
x=1/3,x=9

回答(3):

(X-1)(X-6)=0
(5X-1)(5X-4)=0
(3X-1)(X-9)=0

回答(4):

2+5=10