解答：函数f(x+2)的定义域是【-2,3】∴ x∈[-2,3]∴ x+2∈[0,5]即 f法则只对【0,5】内的数有效要求f(x-2)的定义域即 x-2∈[0,5]∴ x∈[2,7]即 f(x-2)的定义域是[2,7]
即-2<=x<=30<=x+2<=5所以f(x)定义域是[0,5]则f(x-2)中0<=x-2<=52<=x<=7所以定义域是[2,7]
