串联电路中,电阻越大,两端分配到的电压也越大。怎么理解

2025-03-15 05:55:27
推荐回答(3个)
回答(1):

嗯,其实老师说的这个补充也不是很对。一个电阻R也可以说电阻越大电压越大,只不过是电压变大了一点点。下面来解释:

一个电路中除了外界电阻R之外,电源还有自己的内阻r,
这个r相当于串联在电路中。而设电源电压为U,当电路中有一个R时,R两端电压=U*R/(r+R),由于r很小很小,中学课本将其忽略,所以当只有一个外界电阻R时,R两端电压=电源电压U,其数值不随电阻R变化而变化。

而当电路中有2个以上R时,R两端电压=U*(R/(R+R1)),所以当R增大时,R两端电压也会随之而增大。

回答(2):

因为在串联电路中,电流处处相等,根据欧姆定律I=U/R

得出,当通过导体的电流一定时,加在导体两端的电压和导体的电阻成正比。

所以导体电阻越大,分配在导体两端的电压就越多。

反之,导体电阻越小,分配在导体两端的电压就越少。

回答(3):

因为在串联电路中电流时处处相等的,根据U=I*R,通过所有电阻的电流I都是相等的,所以R越大两端电压也就越大,并且有R1:R2:R3……=U1:U2:U3……

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