已知圆弧直线距离L=23.24米～弧高H=2.66米，求圆半径R和弧长C?弧所对的圆心角为A。R=H/2+L^2/(8*H)=2.66/2+23.24^2/(8*2.66)=26.7105米A=2*ARC COS((R-H)/R)=2*ARC COS((26.7105-2.66)/26.7105)=51.575度C=π*R*A/180=π*26.7105*51.575/180=24.0436米
