f(x)=3x²+5x-2f(3)=3·3²+5·3-2=27+15-2=40f(a)=3(a+1)²+5(a+1)-2 =3a²+6a+3+5a+5-2 =3a²+11a+6(2)f(a)=3a²+5a-2=-43a²+5a+2=0(a+1)(3a+2)=0a₁=-1 a₂=-2/3
