西葫芦的果形由两对等位基因(A与a、B与b)控制,果皮的颜色由两对等位基因(W与w、Y与y)控制,这四对基

2025-04-07 21:34:25
推荐回答(1个)
回答(1):

(1)已知圆球形果的基因型是A-bb或aaB-,扁盘形的基因型是A-B-,根据甲组实验圆形球果×圆形球果→F1全部是扁盘形果,可知两亲本是AAbb、aaBB,F1是AaBb.所以F1的扁盘形(AaBb)自交,后代的基因型及比例为A-B-:A-bb:aaB-:aabb=9:3:3:1,故表现型及比例为扁盘形果:圆球形果:长圆形果=9:6:1.
(2)乙组实验扁盘形(AaBb)与长圆形(aabb)杂交,后代F1出现了扁盘形果、圆球形果、长圆形果,说明乙组亲本中扁盘形果的基因型为AaBb,且F1出现了扁盘形果(AaBb)、圆球形果(A-bb或aaB-)、长圆形果(aabb)=1:2:1.如下图所示:

(3)丙组实验中白皮果(W-Y-、W-yy)×黄皮果(wwY-)→F1:白皮果(W-Y-或W-yy):黄皮果(wwY-):绿皮果(wwyy)=4:3:1,其中绿皮果(wwyy)占

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,说明亲本黄皮果的基因型是wwYy,白皮果基因型是WwYy,所以F1中白皮果的基因型为WwYY、WwYy和Wwyy,黄皮纯合子wwYY所占的比例为
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故答案是:
(1)扁盘形果:圆球形果:长圆形果=9:6:1
(2)AaBb  柱状图如下

(3)WwYY、WwYy和Wwyy  
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