一道概率论问题求解,需要过程!

2024-11-22 01:57:59
推荐回答(1个)
回答(1):

P(A)=0.92, P(B)=0.3, P(B|~A) =0.85
P(AUB)
=P(A)+P(B) - P(A∩B)
=P(A)+P(B) - [ P(B) -P(B∩~A) ]
=P(A)+P(B) - [ P(B) -P(~A).P(B|~A) ]
=P(A)+P(B) - [ P(B) -( 1-P(A)) .P(B|~A) ]
=0.92 +0.3 - [ 0.3 - ( 1-0.92)(0.85) ]
=0.988