解:(3+3/4÷3/4+3)-(7×1/6÷7x1/6)=(3+1+3)-(7/6*6/7)=6。
(3+3/4÷3/4+3)-(7×1/6÷7x1/6)=(3+1+3)-(7÷7×1/6x1/6)=7-1/36=6又36分之35
(3+3/4÷3/4+3)-(7×1/6÷7x1/6)=(3+1+3)-(1/6×1/6)=7-1/36=6又36分之35
=7-1=6