某同学欲用已知物质的量浓度的盐酸来测定未知物质的量浓度的NaOH溶液时,选择甲基橙作指示剂.请回答下列

2025-04-07 05:43:19
推荐回答(1个)
回答(1):

(1)酸碱中和滴定时,眼睛要注视锥形瓶内溶液的颜色变化;滴定终点时溶液颜色由黄色突变为橙色,且半分钟内不复原,
故答案为:锥形瓶中溶液颜色变化;半分钟内不复原;
(2)A、酸式滴定管未用标准盐酸溶液润洗就直接注入标准盐酸溶液,标准液的浓度偏小,造成V(标准)偏大,根据c(待测)=

c(标准)×V(标准)
V(待测)
,可知c(待测)偏大,故A错误;
B、滴定前盛放氢氧化钠溶液的锥形瓶用蒸馏水洗净后没有干燥,待测液的物质的量不变,对V(标准)无影响,根据c(待测)=
c(标准)×V(标准)
V(待测)
,可知c(待测)不变,故B错误;
C、酸式滴定管在滴定前有气泡,滴定后气泡消失,造成V(标准)偏大,根据c(待测)=
c(标准)×V(标准)
V(待测)
,可知c(待测)偏大,故C错误;
D、读取盐酸体积时,开始仰视读数,滴定结束时俯视读数,造成V(标准)偏小,根据c(待测)=
c(标准)×V(标准)
V(待测)
,可知c(待测)偏小,故D正确;
故选:D;
(3)起始读数为0.00mL,终点读数为26.10mL,盐酸溶液的体积为26.10mL;
故答案为:0.00;26.10;26.10.

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